Question
2x2 - (4 + √13)x + 2 √13 = 0
10y2 - (18 + 5 √13)y + 9 √13 = 0
Solution
(c); 2x2 - 4x - √13x + 2 √13 = 0
2x (x - 2) √13 (x - 2) = 0
x = 2, √13/2
10y2 - 18y - 5 √13y + 9 √13 = 0
2y(5y - 9) - √13(5y - 9) = 0
y = 9/5, √13/2
x ≥ y
(c); 2x2 - 4x - √13x + 2 √13 = 0
2x (x - 2) √13 (x - 2) = 0
x = 2, √13/2
10y2 - 18y - 5 √13y + 9 √13 = 0
2y(5y - 9) - √13(5y - 9) = 0
y = 9/5, √13/2
x ≥ y
