• Numerical Ability - Number Series
Question

3  9  23  99  479  2881  20159

  • A) 9
  • B) 23
  • C) 99
  • D) 479
  • E) 2881
Solution

The series is 3 × 2 + 3 = 9, 9 × 3 4 = 23, 23 × 4 + 5 = 97, 97 × 5 6 = 479, 479 × 6 + 7 =
2881, 2881 × 7 8 = 20159
Hence, there should be 97 in place of 99.

The series is 3 × 2 + 3 = 9, 9 × 3 4 = 23, 23 × 4 + 5 = 97, 97 × 5 6 = 479, 479 × 6 + 7 =
2881, 2881 × 7 8 = 20159
Hence, there should be 97 in place of 99.
Comments