• Numerical Ability - Quadratic Equations
Question

4x² + 25x + 21 = 0
3y² + 29y + 56 = 0

  • A) X > Y
  • B) X < Y
  • C) X ≥ Y
  • D) X ≤ Y
  • E) X = Y or relation cannot be established
Solution

E. X = Y or relation cannot be established
Explanation:
4x² + 25x + 21 = 0
x = -1, – 5.25
3y² + 29y + 56 = 0
y = -7, -2.6

E. X = Y or relation cannot be established
Explanation:
4x² + 25x + 21 = 0
x = -1, – 5.25
3y² + 29y + 56 = 0
y = -7, -2.6
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