Question
A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:
Solution
Let S be the sample space.
Then, n(S) = number of ways of drawing 3 balls out of 15 = 15C315C3 =15*14*133*2*115*14*133*2*1= 455.
Let E = event of getting all the 3 red balls.
n(E) = 5C35C3 = 5*42*15*42*1 = 10.
=> P(E) = n(E)/n(S) = 10/455 = 2/91.
Let S be the sample space.
Then, n(S) = number of ways of drawing 3 balls out of 15 = 15C315C3 =15*14*133*2*115*14*133*2*1= 455.
Let E = event of getting all the 3 red balls.
n(E) = 5C35C3 = 5*42*15*42*1 = 10.
=> P(E) = n(E)/n(S) = 10/455 = 2/91.
