Question
Two dice are tossed. The probability that the total score is a prime number is:
Solution
Answer (E): None of these
Explanation:
Clearly, n(S) = (6 × 6) = 36
Let E = Event that the sum is a prime number.
Then = {(1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3), (5,2), (5, 6), (6, 1), (6, 5)}
n(E) = 15
P(E) =n(E)/n(E) - 15/36 = 5/12.
Answer (E): None of these
Explanation:
Clearly, n(S) = (6 × 6) = 36
Let E = Event that the sum is a prime number.
Then = {(1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3), (5,2), (5, 6), (6, 1), (6, 5)}
n(E) = 15
P(E) =n(E)/n(E) - 15/36 = 5/12.
