• Numerical Ability - Quadratic Equations
Question

x² – 32x + 252 = 0
y² – 28y + 192 = 0

  • A) X > Y
  • B) X < Y
  • C) X ≥ Y
  • D) X ≤ Y
  • E) X = Y or relation cannot be established
Solution

E. X = Y or relation cannot be established
Explanation:
x² – 32x + 252 = 0
x = 18, 14
y² – 28y + 192 = 0
y = 12, 16

E. X = Y or relation cannot be established
Explanation:
x² – 32x + 252 = 0
x = 18, 14
y² – 28y + 192 = 0
y = 12, 16
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