• Numerical Ability - Quadratic Equations
Question

x² + 40x + 391 = 0
y² – 20y – 525 = 0

  • A) X > Y
  • B) X < Y
  • C) X ≥ Y
  • D) X ≤ Y
  • E) X = Y or relation cannot be established
Solution

B. X < Y
Explanation:
x² + 40x + 391 = 0
x = -23, -17
y² – 20y – 525 = 0
y = 35, – 15

B. X < Y
Explanation:
x² + 40x + 391 = 0
x = -23, -17
y² – 20y – 525 = 0
y = 35, – 15
Comments