• Numerical Ability - Quadratic Equations
Question

x(10x – 1) = 2
4y² + 3y – 27 = 0

  • A) X > Y
  • B) X < Y
  • C) X ≥ Y
  • D) X ≤ Y
  • E) X = Y or relation cannot be established
Solution

E. X = Y or relation cannot be established
Explanation:
x(10x – 1) = 2
10x2 – x – 2 = 0; x = 0.5, -0.4
4y² + 3y – 27 = 0
y = -3, 2.25

E. X = Y or relation cannot be established
Explanation:
x(10x – 1) = 2
10x2 – x – 2 = 0; x = 0.5, -0.4
4y² + 3y – 27 = 0
y = -3, 2.25
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