• Numerical Ability - Quadratic Equations
Question

I. (6x2 + 17) - (3x2 + 20) = 0

II. (5y2 - 12) - (9y2 - 16) = 0

  • A) if x > y
  • B) if x ≥  y
  • C) if x < y
  • D) if x ≤ y
  • E) if x = y or relationship cannot be established
Solution

Answer: (e)

Explanation:

6x2  + 17 – 3x2  – 20 = 0 … (i) or,

3x2  = 3

x ± l

5y2– 12 -9y2+ 16 =0 …. (ii)

or, 4y2 = 4

y ± 1

Hence x = y.

Answer: (e)

Explanation:

6x2  + 17 – 3x2  – 20 = 0 … (i) or,

3x2  = 3

x ± l

5y2– 12 -9y2+ 16 =0 …. (ii)

or, 4y2 = 4

y ± 1

Hence x = y.
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