Question
I. 2x2- (4 ÷√13)x + 2√13 = 0
II. (5y2-12)-(9y2-16)=0
Solution
Answer: (b)
Explanation:
2x2 – 4x – √13 x + 2 = 0…(i)
or,2x (x-2) – √13 (x-2) = 0
or, (x-2) (2x – √13) = 0
x = 2, √13/2
10y2 – 18y – 5√13y +9√13 = 0…(ii)
or,2y (5y-9) – √13 (5y-9) = 0
or,(2y-√13) (5y – 9) = 0
y = 9/5, √13/2
10y2 – 18y – 5√13y + 9 √13 = 0 ……………(ii)
or 2y (5y – 9) – √13 (5y-9) = 0
y = 9/5, √13/2
Hence, x y.
Answer: (b)
Explanation:
2x2 – 4x – √13 x + 2 = 0…(i)
or,2x (x-2) – √13 (x-2) = 0
or, (x-2) (2x – √13) = 0
x = 2, √13/2
10y2 – 18y – 5√13y +9√13 = 0…(ii)
or,2y (5y-9) – √13 (5y-9) = 0
or,(2y-√13) (5y – 9) = 0
y = 9/5, √13/2
10y2 – 18y – 5√13y + 9 √13 = 0 ……………(ii)
or 2y (5y – 9) – √13 (5y-9) = 0
y = 9/5, √13/2
Hence, x y.
